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1.void pointer can point to any data type, that is, any data type of pointer can assign to void pointer; E.G.

what type of data is pointed to by the void pointer. memcpy, qsort and many others.. Why is that? When you successively increment the result, up to the size of int (4 bytes), you can display the remaining bytes of the variable.

In// binary, that means it must be a 1. Is it a type that can be assigned from any type pointer, but interprets the number as an unsigned int when you dereference it? It would be incorrect, if we assign an address of a float variable to a pointer of type pointer to int.But void pointer is an exception to this rule. Ultimately, that is up to you to keep track of.Although some compilers allow deleting a void pointer that points to dynamically allocated memory, doing so should be avoided, as it can result in undefined behavior.It is not possible to do pointer arithmetic on a void pointer. Declare a pointer p as void. int* p: p is a pointer to an integer. 1 Now void pointers are a pointer that does not specify the data type at the type of declaration, and it can point to any type of variable, just need to specify the data type that is to be assigned. The void pointer, also known as the generic pointer, is a special type of pointer that can be pointed at objects of any data type! Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.
09-20-2008 #4 Can you do this with it: [EDIT]: You can't, but I can't figure out how you would use it. By Max_Payne in forum C++ Programming In this chapter we will be looking special type of pointer called void pointer or general purpose pointer. 1 asterisk for pointer elements, the other for array.// Truncates a 32-bit floating point number encoded according to the IEEE 754 standard.// The mantissa in a 32-bit IEEE 754 float is the 23 least significant bits.// Copy the argument to retain all info even after manipulating the number and// reinterpret the 32 bits in memory as an int to enable bitshifts.// Shift the bits so that the exponent is in the eight least significant bits.// Mask out the 8 least signinficant digits of the number// exp should be >= 127 by now, since we handled the cases of a negative exp// already by testing if -1 < f < 1. The following program demonstrates pointer arithmetic in void pointers.The void pointers are used extensively in dynamic memory allocation which we will discuss next.// wrong since type of fp is pointer to float Now that we have an `int*`, we can dereference it with the `*` operator and get the value that the pointer is pointing to. Before going further it will be good if you refresh about pointers by reading – Introduction to pointers in C. A pointer variable is usually declared with the data type of the “content” that is to be stored inside the memory location (to which the pointer variable points to). ?And also, why we could call the function using: 'printValue(szValue, Type::CSTRING)', because doesn't it mean that: int *p==szValue?? Don’t stop learning now. Otherwise, an if-statement is easier to read.Bear in mind that the internal representation of floating pointer numbers is not standardized in C++. We can thus safely subtract 127 from it// without having overflow to get the actual positive value of the exponent.// If the exponent is zero, the truncated number must be +/- 1, since there// can only be one digit before the point and it must be non-zero.

Similar story for all fixed width ints: it doesn't autocomplete the std:: version.

Just make sure there isn’t a better (safer) way to do the same thing using other language mechanisms first!1) What’s the difference between a void pointer and a null pointer?I couldn't follow the below statements. int*[] p: p is a single-dimensional array of pointers to integers. Declare b of the float datatype. `int*`. A void pointer must be explicitly cast into another type of pointer to be dereferenced. We can thus safely subtract 127 from it// without having overflow to get the actual positive value of the exponent.// If the exponent is zero, the truncated number must be +/- 1, since there// can only be one digit before the point and it must be non-zero. You can't do it directly.